3n^2+8n+16=2n^2

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Solution for 3n^2+8n+16=2n^2 equation: 



3n^2+8n+16=2n^2

We move all terms to the left:

3n^2+8n+16-(2n^2)=0

determiningTheFunctionDomain
3n^2-2n^2+8n+16=0

We add all the numbers together, and all the variables

n^2+8n+16=0

a = 1; b = 8; c = +16;
Δ = b2-4ac
Δ = 82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-8}{2}=-4$

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